{"id":23537,"date":"2023-01-28T15:26:05","date_gmt":"2023-01-28T08:26:05","guid":{"rendered":"https:\/\/kiencang.net\/?p=23537"},"modified":"2023-08-26T17:59:27","modified_gmt":"2023-08-26T10:59:27","slug":"tim-kiem-nhi-phan","status":"publish","type":"post","link":"https:\/\/kiencang.net\/tim-kiem-nhi-phan\/","title":{"rendered":"T\u00ecm ki\u1ebfm nh\u1ecb ph\u00e2n [serial v\u1ec1 c\u00e1c thu\u1eadt to\u00e1n c\u01a1 b\u1ea3n trong l\u1eadp tr\u00ecnh]"},"content":{"rendered":"\n

T\u00ecm ki\u1ebfm nh\u1ecb ph\u00e2n (binary search) l\u00e0 m\u1ed9t trong c\u00e1c thu\u1eadt to\u00e1n c\u01a1 b\u1ea3n trong l\u1eadp tr\u00ecnh m\u00e0 ch\u00fang ta c\u0169ng c\u1ea7n ph\u1ea3i bi\u1ebft. \u01afu \u0111i\u1ec3m c\u1ee7a n\u00f3 l\u00e0 t\u1ed1c \u0111\u1ed9 t\u1ed1t (v\u00ed d\u1ee5 khi so v\u1edbi t\u00ecm ki\u1ebfm tuy\u1ebfn t\u00ednh \/ tu\u1ea7n t\u1ef1<\/a>) tr\u00ean c\u00e1c m\u1ea3ng c\u00f3 s\u1ed1 l\u01b0\u1ee3ng ph\u1ea7n t\u1eed l\u1edbn, ngo\u00e0i ra, t\u00ecm ki\u1ebfm nh\u1ecb ph\u00e2n c\u0169ng d\u1ec5 hi\u1ec3u n\u1eefa.<\/p>\n\n\n\n

M\u1ed9t y\u00eau c\u1ea7u trong t\u00ecm ki\u1ebfm nh\u1ecb ph\u00e2n l\u00e0 m\u1ea3ng m\u00e0 n\u00f3 c\u1ea7n t\u00ecm ki\u1ebfm c\u1ea7n ph\u1ea3i \u0111\u01b0\u1ee3c s\u1eafp x\u1ebfp<\/a> r\u1ed3i (ch\u1eb3ng h\u1ea1n b\u1eb1ng quick sort<\/a>). <\/p>\n\n\n\n

V\u00ed d\u1ee5, h\u00e3y t\u00ecm v\u1ecb tr\u00ed c\u1ee7a gi\u00e1 tr\u1ecb 75 trong m\u1ea3ng sau: <\/p>\n\n\n\n

1, 3, 4, 7, 9, 32, 45, 57, 68, 75, 92, 101<\/code><\/pre>\n\n\n\n

N\u1ebfu trong t\u00ecm ki\u1ebfm tuy\u1ebfn t\u00ednh, n\u00f3 s\u1ebd duy\u1ec7t qua t\u1ea5t c\u1ea3 ph\u1ea7n t\u1eed c\u1ee7a m\u1ea3ng, r\u1ed3i so kh\u1edbp xem ph\u1ea7n t\u1eed \u0111\u00f3 c\u00f3 \u0111\u00fang l\u00e0 ph\u1ea7n t\u1eed c\u1ea7n t\u00ecm ki\u1ebfm kh\u00f4ng, sau \u0111\u00f3 tr\u1ea3 v\u1ec1 k\u1ebft qu\u1ea3 v\u1ecb tr\u00ed. <\/p>\n\n\n\n

T\u00ecm ki\u1ebfm nh\u1ecb ph\u00e2n ho\u1ea1t \u0111\u1ed9ng th\u00f4ng minh h\u01a1n, v\u00ec m\u1ea3ng \u0111\u00e3 \u0111\u01b0\u1ee3c s\u1eafp x\u1ebfp, n\u00ean n\u00f3 chia \u0111\u00f4i m\u1ea3ng ra th\u00e0nh 2 m\u1ea3ng nh\u1ecf l\u00e0 A v\u00e0 B, r\u1ed3i \u0111em so s\u00e1nh ph\u1ea7n t\u1eed c\u1ea7n t\u00ecm ki\u1ebfm v\u1edbi ph\u1ea7n t\u1eed cu\u1ed1i c\u1ee7a m\u1ea3ng A, n\u1ebfu n\u00f3 \u0111\u00fang b\u1eb1ng ph\u1ea7n t\u1eed n\u00e0y th\u00ec \u0111\u00e2y l\u00e0 ph\u1ea7n t\u1eed c\u1ea7n t\u00ecm, n\u1ebfu n\u00f3 nh\u1ecf h\u01a1n th\u00ec ph\u1ea7n t\u1eed c\u1ea7n t\u00ecm s\u1ebd n\u1eb1m trong m\u1ea3ng A, n\u1ebfu n\u00f3 l\u1edbn h\u01a1n th\u00ec ph\u1ea7n t\u1eed c\u1ea7n t\u00ecm s\u1ebd n\u1eb1m trong m\u1ea3ng B. <\/p>\n\n\n\n

Nh\u01b0 v\u1eady, th\u00f4ng qua m\u1ed9t thao t\u00e1c so s\u00e1nh, n\u00f3 \u0111\u1ee1 \u0111\u01b0\u1ee3c 1\/2 c\u00f4ng s\u1ee9c duy\u1ec7t c\u1ea3 m\u1ea3ng, kh\u00f4ng gian t\u00ecm ki\u1ebfm c\u1ee7a n\u00f3 thu h\u1eb9p r\u1ea5t nhanh, gi\u00fap qu\u00e1 tr\u00ecnh n\u00e0y c\u00f3 t\u1ed1c \u0111\u1ed9 t\u1ed1t. Qu\u00e1 tr\u00ecnh ph\u00e2n \u0111\u00f4i (nh\u1ecb ph\u00e2n) n\u00e0y c\u1ee9 ti\u1ebfp t\u1ee5c cho \u0111\u1ebfn khi n\u00f3 t\u00ecm \u0111\u01b0\u1ee3c v\u1ecb tr\u00ed ch\u00ednh x\u00e1c.<\/p>\n\n\n\n

\u0110o\u1ea1n m\u00e3 PHP \u0111\u1ec3 l\u00e0m vi\u1ec7c n\u00e0y:<\/p>\n\n\n\n

function binary_search($arr, $x)\n{\n    $left = 0;\n    $right = count($arr) - 1;\n    while ($left <= $right) {\n        $mid = intval(($left + $right) \/ 2); \/\/ l\u1ea5y ph\u1ea7n nguy\u00ean\n        if($arr[$mid] == $x) { \/\/ n\u1ebfu \u0111\u00fang b\u1eb1ng gi\u00e1 tr\u1ecb c\u1ea7n t\u00ecm\n            return $mid; \/\/ ra \u0111\u01b0\u1ee3c v\u1ecb tr\u00ed\n            $left = $right + 1; \/\/ k\u1ebft th\u00fac\n        }\n        else if ($x < $arr[$mid]) {\n\/\/ b\u1ecf \u0111i ph\u1ea7n t\u1eed $arr[$mid], kh\u00f4ng ph\u1ea3i so n\u1eefa, v\u00e0 thu h\u1eb9p v\u00f9ng t\u00ecm ki\u1ebfm\n            $right = $mid - 1; \n        }\n        else {\n\/\/ b\u1ecf \u0111i ph\u1ea7n t\u1eed $arr[$mid], kh\u00f4ng ph\u1ea3i so n\u1eefa, v\u00e0 thu h\u1eb9p v\u00f9ng t\u00ecm ki\u1ebfm\n            $left = $mid + 1;\n        }\n    }\n\/\/ khi n\u00f3 kh\u00f4ng t\u00ecm th\u1ea5y\n    return -1;\n}\n\n$arr = array(1, 3, 4, 7, 9, 32, 45, 57, 68, 75, 92, 101);\necho  binary_search($arr, 75); \/\/ k\u1ebft qu\u1ea3 l\u00e0 9, l\u00e0 v\u1ecb tr\u00ed c\u1ee7a ph\u1ea7n t\u1eed 75 trong m\u1ea3ng<\/code><\/pre>\n\n\n\n

Qu\u00e1 tr\u00ecnh n\u00e0y di\u1ec5n ti\u1ebfn nh\u01b0 sau:<\/p>\n\n\n\n

L\u1ea7n 1:<\/p>\n\n\n\n

    \n
  • $left = 0, $right = 11, $mid = 5, $arr[5] = 32. <\/li>\n\n\n\n
  • M\u1ea3ng A1 = 1, 3, 4, 7, 9, 32<\/li>\n\n\n\n
  • M\u1ea3ng B1 = 45, 57, 68, 75, 92, 101<\/li>\n\n\n\n
  • V\u00ec 75 > 32, n\u00ean ph\u1ea7n t\u1eed c\u1ea7n t\u00ecm n\u1ebfu c\u00f3 ch\u1eafc ch\u1eafn kh\u00f4ng thu\u1ed9c A1, do v\u1eady n\u00f3 t\u00ecm ti\u1ebfp trong B1, v\u1edbi qu\u00e1 tr\u00ecnh t\u01b0\u01a1ng t\u1ef1.<\/li>\n\n\n\n
  • $left \u0111\u01b0\u1ee3c c\u1eadp nh\u1eadt gi\u00e1 tr\u1ecb m\u1edbi l\u00e0 $left = 5 + 1 = 6<\/li>\n<\/ul>\n\n\n\n

    L\u1ea7n 2:<\/p>\n\n\n\n

      \n
    • $left = 6, $right = 11, $mid = 8, $arr[8] = 68.<\/li>\n\n\n\n
    • M\u1ea3ng A2 = 45, 57, 68<\/li>\n\n\n\n
    • B\u1ea3ng B2 = 75, 92, 101<\/li>\n\n\n\n
    • V\u00ec 75 > 68, n\u00ean ph\u1ea7n t\u1eed c\u1ea7n t\u00ecm n\u1ebfu c\u00f3 ch\u1eafc ch\u1eafn kh\u00f4ng thu\u1ed9c A2, do v\u1eady n\u00f3 t\u00ecm ti\u1ebfp trong B2, v\u1edbi qu\u00e1 tr\u00ecnh t\u01b0\u01a1ng t\u1ef1.<\/li>\n\n\n\n
    • $left \u0111\u01b0\u1ee3c c\u1eadp nh\u1eadt gi\u00e1 tr\u1ecb m\u1edbi l\u00e0 $left = 8 + 1 = 9<\/li>\n<\/ul>\n\n\n\n

      L\u1ea7n 3: <\/p>\n\n\n\n

        \n
      • $left = 9, $right = 11, $mid = 10, $arr[10] = 92.<\/li>\n\n\n\n
      • M\u1ea3ng A3 = 75, 92<\/li>\n\n\n\n
      • M\u1ea3ng B3 = 101<\/li>\n\n\n\n
      • V\u00ec 75 < 92, n\u00ean ph\u1ea7n t\u1eed c\u1ea7n t\u00ecm n\u1ebfu c\u00f3 ch\u1eafc ch\u1eafn kh\u00f4ng thu\u1ed9c B3, do v\u1eady n\u00f3 t\u00ecm ti\u1ebfp trong A3, v\u1edbi qu\u00e1 tr\u00ecnh t\u01b0\u01a1ng t\u1ef1.<\/li>\n\n\n\n
      • $right \u0111\u01b0\u1ee3c c\u1eadp nh\u1eadt l\u00e0 $right = 11 – 1 = 10<\/li>\n<\/ul>\n\n\n\n

        L\u1ea7n 4:<\/p>\n\n\n\n

          \n
        • $left = 9, $right = 10, $mid = 9, $arr[9] = 75.<\/li>\n\n\n\n
        • V\u00ec 75 = $arr[9], n\u00f3 t\u00ecm \u0111\u01b0\u1ee3c v\u1ecb tr\u00ed c\u1ea7n t\u00ecm, \u1edf \u0111\u00e2y c\u00f3 gi\u00e1 tr\u1ecb l\u00e0 9.<\/li>\n<\/ul>\n\n\n\n
          \n\n\n\n

          M\u1ed9t s\u1ed1 l\u01b0u \u00fd:<\/p>\n\n\n\n

            \n
          • T\u00ecm ki\u1ebfm nh\u1ecb ph\u00e2n ch\u1ec9 ho\u1ea1t \u0111\u1ed9ng tr\u00ean m\u1ea3ng \u0111\u00e3 s\u1eafp x\u1ebfp, n\u00ean n\u1ebfu m\u1ea3ng ch\u01b0a s\u1eafp x\u1ebfp, ch\u00fang ta c\u1ea7n s\u1eafp x\u1ebfp l\u1ea1i n\u00f3 tr\u01b0\u1edbc khi d\u00f9ng t\u00ecm ki\u1ebfm nh\u1ecb ph\u00e2n.<\/li>\n\n\n\n
          • Tr\u00ean c\u00e1c m\u1ea3ng c\u00f3 s\u1ed1 l\u01b0\u1ee3ng ph\u1ea7n t\u1eed nh\u1ecf, t\u00ecm ki\u1ebfm tuy\u1ebfn t\u00ednh c\u00f3 th\u1ec3 hi\u1ec7u qu\u1ea3 h\u01a1n.<\/li>\n\n\n\n
          • Hi\u1ec7u qu\u1ea3 c\u1ee7a t\u00ecm ki\u1ebfm nh\u1ecb ph\u00e2n l\u00e0 cao nh\u1ea5t khi s\u1eed d\u1ee5ng tr\u00ean c\u00e1c m\u1ea3ng c\u00f3 s\u1ed1 l\u01b0\u1ee3ng ph\u1ea7n t\u1eed l\u1edbn. Tuy m\u1ea5t th\u1eddi gian ph\u1ea3i s\u1eafp x\u1ebfp l\u1ea1i ph\u1ea7n t\u1eed l\u00fac ban \u0111\u1ea7u, nh\u01b0ng v\u00ec vi\u1ec7c n\u00e0y ch\u1ec9 ph\u1ea3i l\u00e0m m\u1ed9t l\u1ea7n, trong khi \u0111\u00f3 th\u1eddi gian ti\u1ebft ki\u1ec7m \u0111\u01b0\u1ee3c khi th\u1ef1c hi\u1ec7n bi\u1ec7n ph\u00e1p t\u00ecm ki\u1ebfm nh\u1ecb ph\u00e2n l\u00e0 \u0111\u00e1ng k\u1ec3 v\u00e0 \u0111\u01b0\u1ee3c t\u00edch l\u0169y m\u1ed7i khi th\u1ef1c hi\u1ec7n.<\/li>\n<\/ul>\n","protected":false},"excerpt":{"rendered":"

            T\u00ecm ki\u1ebfm nh\u1ecb ph\u00e2n (binary search) l\u00e0 m\u1ed9t trong c\u00e1c thu\u1eadt to\u00e1n c\u01a1 b\u1ea3n trong l\u1eadp tr\u00ecnh m\u00e0 ch\u00fang ta c\u0169ng c\u1ea7n ph\u1ea3i bi\u1ebft. \u01afu \u0111i\u1ec3m c\u1ee7a n\u00f3 l\u00e0 t\u1ed1c \u0111\u1ed9 t\u1ed1t (v\u00ed d\u1ee5 khi so v\u1edbi t\u00ecm ki\u1ebfm tuy\u1ebfn t\u00ednh \/ tu\u1ea7n t\u1ef1) tr\u00ean c\u00e1c m\u1ea3ng c\u00f3 s\u1ed1 l\u01b0\u1ee3ng ph\u1ea7n t\u1eed l\u1edbn, ngo\u00e0i ra, …<\/p>\n","protected":false},"author":1,"featured_media":24638,"comment_status":"open","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"footnotes":""},"categories":[333],"tags":[335],"yoast_head":"\nT\u00ecm ki\u1ebfm nh\u1ecb ph\u00e2n [serial v\u1ec1 c\u00e1c thu\u1eadt to\u00e1n c\u01a1 b\u1ea3n trong l\u1eadp tr\u00ecnh] • Ki\u1ebfn c\u00e0ng<\/title>\n<meta name=\"robots\" content=\"index, follow, max-snippet:-1, max-image-preview:large, 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c\u0169ng c\u1ea7n ph\u1ea3i bi\u1ebft. \u01afu \u0111i\u1ec3m c\u1ee7a n\u00f3 l\u00e0 t\u1ed1c \u0111\u1ed9 t\u1ed1t (v\u00ed d\u1ee5 khi so v\u1edbi t\u00ecm ki\u1ebfm tuy\u1ebfn t\u00ednh \/ tu\u1ea7n t\u1ef1) tr\u00ean c\u00e1c m\u1ea3ng c\u00f3 s\u1ed1 l\u01b0\u1ee3ng ph\u1ea7n t\u1eed l\u1edbn, ngo\u00e0i ra, …","og_url":"https:\/\/kiencang.net\/tim-kiem-nhi-phan\/","og_site_name":"Ki\u1ebfn c\u00e0ng","article_author":"https:\/\/www.facebook.com\/anhducnguyen87\/","article_published_time":"2023-01-28T08:26:05+00:00","article_modified_time":"2023-08-26T10:59:27+00:00","og_image":[{"width":1200,"height":628,"url":"https:\/\/kiencang.net\/wp-content\/uploads\/2023\/01\/tim-kiem-nhi-phan.png","type":"image\/png"}],"author":"Nguy\u1ec5n \u0110\u1ee9c Anh","twitter_card":"summary_large_image","twitter_misc":{"\u0110\u01b0\u1ee3c vi\u1ebft b\u1edfi":"Nguy\u1ec5n \u0110\u1ee9c Anh","\u01af\u1edbc t\u00ednh th\u1eddi gian \u0111\u1ecdc":"5 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