\\.<\/code><\/li><\/ul>\n\n\n\nV\u00ed d\u1ee5 \u0111\u1ec3 kh\u1edbp ng\u00e0y th\u00e1ng c\u00f3 c\u1ea5u tr\u00fac ki\u1ec3u nh\u01b0 2.3 (ng\u00e0y m\u00f9ng 2 th\u00e1ng 3) b\u1ea1n s\u1ebd ph\u1ea3i vi\u1ebft th\u1ebf n\u00e0y \\d\\.\\d<\/code> (tr\u00f4ng v\u1eabn qu\u00e1i d\u1ecb nh\u01b0ng gi\u1edd d\u1ec5 hi\u1ec3u h\u01a1n r\u1ed3i! N\u00f3 c\u00f3 ngh\u0129a l\u00e0 s\u1ed1 r\u1ed3i ti\u1ebfp \u0111\u1ebfn l\u00e0 . r\u1ed3i l\u1ea1i l\u00e0 s\u1ed1)<\/p>\n\n\n\n- V\u00ed d\u1ee5 tr\u00ean \u0111\u00e3 \u00e2m th\u1ea7m n\u00f3 \u0111\u1ebfn m\u1ed9t th\u1ee9 ph\u1ee9c t\u1ea1p h\u01a1n \u0111\u00f3 l\u00e0 th\u1ee9 t\u1ef1 trong RegEx. \\d ch\u1ec9 \u0111\u1ea1i di\u1ec7n cho m\u1ed9t s\u1ed1, c\u0169ng v\u1eady [0-9] c\u0169ng ch\u1ec9 \u0111\u1ea1i di\u1ec7n cho m\u1ed9t s\u1ed1 khi m\u00e0 c\u00f3 s\u1ef1 k\u1ebft h\u1ee3p;<\/li>
- N\u1ebfu ch\u1ec9 c\u00f3
\\d<\/code> n\u00f3 s\u1ebd kh\u1edbp v\u1edbi c\u1ea3 67 l\u1eabn 6, nh\u01b0ng n\u1ebfu l\u00e0 \\d\\d<\/code> th\u00ec ch\u1ec9 67 l\u00e0 kh\u1edbp, 6 l\u00fac n\u00e0y kh\u00f4ng li\u00ean quan n\u1eefa. V\u00ec \\d\\d<\/code> n\u00f3i r\u1eb1ng chu\u1ed7i c\u1ea7n t\u00ecm ph\u1ea3i c\u00f3 2 s\u1ed1 c\u01a1.<\/li>- C\u0169ng v\u1eady \\d\\.\\d c\u0169ng ch\u1ec9 kh\u1edbp v\u1edbi 6.7 ho\u1eb7c 5.3 ch\u1ee9 23, 45 l\u00fac n\u00e0y kh\u00f4ng li\u00ean quan n\u1eefa v\u00ec 23 v\u00e0 45 l\u00e0m g\u00ec c\u00f3 d\u1ea5u .<\/li>
- T\u01b0\u01a1ng t\u1ef1 [a-z][a-z] th\u00ec n\u00f3 s\u1ebd ch\u1ec9 kh\u1edbp v\u1edbi chu\u1ed7i n\u00e0o c\u00f3 2 k\u00fd t\u1ef1 \u0111\u1ee9ng c\u1ea1nh nhau ch\u1ee9 c\u00f3 1 k\u00fd t\u1ef1 l\u00e0 kh\u00f4ng kh\u1edbp n\u1eefa, ho\u1eb7c k\u1ec3 c\u1ea3 c\u00f3 2 k\u00fd t\u1ef1 nh\u01b0ng ng\u0103n nhau b\u1eb1ng d\u1ea5u c\u00e1ch nh\u01b0 n\u00e0y
a b<\/code> c\u0169ng kh\u00f4ng kh\u1edbp. Mu\u1ed1n kh\u1edbp v\u1edbi chu\u1ed7i a b<\/code> th\u00ec RegEx s\u1ebd ph\u1ea3i l\u00e0 [a-z]\\s[a-z]<\/code><\/li><\/ul>\n\n\n\nGi\u1edd ch\u00fang ta s\u1ebd \u0111i gi\u1ea3i th\u00edch v\u1ea5n \u0111\u1ec1 l\u00e0 t\u1ea1i sao \\d th\u00ec kh\u1edbp v\u1edbi c\u1ea3 67 v\u00e0 6, m\u00e0 \\d\\d th\u00ec l\u1ea1i ch\u1ec9 kh\u1edbp v\u1edbi 67 th\u00f4i ch\u1ee9 kh\u00f4ng c\u00f2n kh\u1edbp v\u1edbi 6 n\u1eefa. C\u00e1i n\u00e0y r\u1ea5t quan tr\u1ecdng \u0111\u1ea5y \u1ea1, t\u00f4i c\u0169ng ch\u1ec9 v\u1eeba m\u1edbi nh\u1eadn ra, v\u00ec \\d c\u0169ng ch\u1ec9 c\u00f3 m\u1ed9t s\u1ed1 th\u00f4i sao n\u00f3 l\u1ea1i kh\u1edbp \u0111\u01b0\u1ee3c v\u1edbi s\u1ed1 c\u00f3 2 s\u1ed1 l\u00e0 67 kia?<\/p>\n\n\n\n
\u0110i\u1ec1u \u0111\u1ea7u ti\u00ean b\u1ea1n c\u1ea7n l\u00e0m l\u00e0 ph\u00f3ng to m\u00e0n h\u00ecnh c\u1ee7a regex101 \u0111\u1ec3 d\u1ec5 quan s\u00e1t.<\/p>\n\n\n\n
V\u1edbi l\u1ec7nh \/d b\u1ea1n s\u1ebd th\u1ea5y n\u00f3 kh\u1edbp v\u1edbi 2 match c\u1ee7a chu\u1ed7i 67 (hai m\u1ea7u xanh nh\u1ea1t v\u00e0 \u0111\u1eadm, b\u1ea1n di con tr\u1ecf chu\u1ed9t v\u00e0o s\u1ebd th\u1ea5y hi\u1ec7n l\u00ean ch\u1eef match 1, match 2). Chu\u1ed7i 6 b\u00ean d\u01b0\u1edbi chi kh\u1edbp 1 l\u1ea7n.<\/p>\n\n\n\n